CUET · CHEMISTRY · PYQ PAPER 2023
The correct shape \(\&\) hybridisation for \(XeF_2\) are:
- A linear, \(sp^3d\)
- B linear, \(sp^3d^2\)
- C trigonal bipyramidal \(sp^3d\)
- D trigonal bipyramidal \(sp^3d^2\)
Answer & Solution
Correct Answer
(A) linear, \(sp^3d\)
Step-by-step Solution
Detailed explanation
Valence electrons in Xe = 8 Valence electrons in 2F = 2 × 7 = 14 Total valence electrons = 8 + 14 = 22 Number of bond pairs = 2 (Xe-F bonds) Number of lone pairs on Xe = (22 - 2 × 2) / 2 = 18 / 2 = 3 Steric number = Number of bond pairs + Number of lone pairs = 2 + 3 = 5…
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