CUET · CHEMISTRY · PYQ PAPER 2025
The correct sequence of reagents to carry out the following conversion is

- A (i) \(\mathrm{Sn} / \mathrm{HCl}\) (ii) Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\) (iii) DIBAL-H (iv) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (v) \(\mathrm{HBF}_4\)
- B (i) Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\) (ii) \(\mathrm{Sn} / \mathrm{HCl}\) (iii) DIBAL-H (iv) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (v) \(\mathrm{HBF}_4\)
- C (i) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (ii) DIBAL-H (iii) \(\mathrm{Sn} / \mathrm{HCl}\) (iv) Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\) (v) \(\mathrm{HBF}_4\)
- D (i) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (ii) DIBAL-H (iii) \(\mathrm{Sn} / \mathrm{HCl}\) (iv) \(\mathrm{HBF}_4\) (v)Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\)
Answer & Solution
Correct Answer
(B) (i) Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\) (ii) \(\mathrm{Sn} / \mathrm{HCl}\) (iii) DIBAL-H (iv) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (v) \(\mathrm{HBF}_4\)
Step-by-step Solution
Detailed explanation
(i) Conc. \(\mathrm{HNO}_3 /\) Conc. \(\mathrm{H}_2 \mathrm{SO}_4\) (ii) \(\mathrm{Sn} / \mathrm{HCl}\) (iii) DIBAL-H (iv) \(\mathrm{NaNO}_2 / \mathrm{HCl}\) (v) \(\mathrm{HBF}_4\)
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