CUET · CHEMISTRY · PYQ PAPER 2023
The correct bond order for the carbon-oxygen bond in the following metal carbonyls \(\left[ Cr ( CO )_6\right],\left[ V ( CO )_6\right]^{-},\left[ Mn ( CO )_6\right]^{+}\)is:
- A \(\left[ V ( CO )_6\right]^{-}<\left[ Cr ( CO )_6\right]<\left[ Mn ( CO )_6\right]^{+}\)
- B \(\left[ V ( CO )_6\right]^{-}=\left[ Cr ( CO )_6\right]=\left[ Mn ( CO )_6\right]^{+}\)
- C \(\left[ Mn ( CO )_8\right]^{+}<\left[ Cr ( CO )_8\right]<\left[ V ( CO )_8\right]^{-}\)
- D \(\left[ Cr ( CO )_8\right]<\left[ V ( CO )_8\right]^{-}<\left[ Mn ( CO )_8\right]^{+}\)
Answer & Solution
Correct Answer
(A) \(\left[ V ( CO )_6\right]^{-}<\left[ Cr ( CO )_6\right]<\left[ Mn ( CO )_6\right]^{+}\)
Step-by-step Solution
Detailed explanation
Higher electron density on metal increases back-bonding, weakening the C-O bond. Order of electron density on metal: \(V(-1) > Cr(0) > Mn(+1)\) Order of C-O bond order: \(\left[ V ( CO )_6\right]^{-}<\left[ Cr ( CO )_6\right]<\left[ Mn ( CO )_6\right]^{+}\)
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