CUET · CHEMISTRY · PYQ PAPER 2023
The activation energy for a reaction at a temperature \(T\) K was found to be \(2.303 RT\) J/mol.
The ratio of the rate constant to Arrhenius factor is:
- A \(10^{-1}\)
- B \(10^{-2}\)
- C \(2 \times 10^{-2}\)
- D \(2 \times 10^{-3}\)
Answer & Solution
Correct Answer
(A) \(10^{-1}\)
Step-by-step Solution
Detailed explanation
\(k = A e^{-E_a / RT}\) \(\frac{k}{A} = e^{-E_a / RT}\) \(\frac{k}{A} = e^{-(2.303 RT) / RT}\) \(\frac{k}{A} = e^{-2.303}\) \(\frac{k}{A} = 10^{-1}\)
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