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CUET · CHEMISTRY · PYQ PAPER 2023

\(t_{99\%}\) with respect to \(t_{90\%}\) for a first order reaction is :

  1. A four times of \(t_{50\%}\)
  2. B one and half time
  3. C It is same
  4. D Double
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Answer & Solution

Correct Answer

(D) Double

Step-by-step Solution

Detailed explanation

\(t_{90\%} = \frac{2.303}{k} \log \frac{[A]_0}{0.10[A]_0} = \frac{2.303}{k} \times 1\) \(t_{99\%} = \frac{2.303}{k} \log \frac{[A]_0}{0.01[A]_0} = \frac{2.303}{k} \times 2\) \(\frac{t_{99\%}}{t_{90\%}} = \frac{2}{1} = 2\)
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