CUET · CHEMISTRY · PYQ PAPER 2025

Relation between equilibrium constant and standard potential of the cell under standard conditions is represented by :

A \(E_{\text {cell }}^{\circ}=\frac{2.303 RT }{F} \log K_c\)
B \(E_{\text {cell }}^{\circ}=\frac{2.303 RT }{n F} \log K_c\)
C \(E_{\text {cell }}^{\circ}=\frac{2.303}{n F} \log K_c\)
D \(E_{\text {cell }}^{\circ}=\frac{2.303 R }{n F} \log K_c\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(E_{\text {cell }}^{\circ}=\frac{2.303 RT }{n F} \log K_c\)

Step-by-step Solution

Detailed explanation

\(E_{\text {cell }}^{\circ}=\frac{2.303 RT }{n F} \log K_c\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the complexes given in List-I with the number of unpaired electrons given in List-II

List-I (Complexes)	List-II (No. Of unpaired electrons.)
(A) \(\left[ Ti \left( H _2 O \right)_6\right]^{3+}\)	(I) 1
(B) \(\left[ NiF _6\right]^{4-}\)	(II) 5
(C) \(\left[ Fe ( CN )_6\right]^{4-}\)	(III) 2
(D) \(\left[ MnF _6\right]^{4-}\)	(IV) 0

Choose the correct answer from the options given below:

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