Read the passage carefully and answer the Questions
Molar conductivity \(\Lambda_m^0\)of a solution at a given concentration (c) is the conductance of volume, V of solution, containing one mole of electrolyte kept between the two electrodes with area of cross-section A and at a distance of unit length. It increases with the decrease in concentration and when the concentration approaches zero, the molar conductivity is called limiting molar conductivity \(\Lambda_m^0\) . For a strong electrolyte, \(\Lambda_m\) increases linearly with dilution and is given by \(\Lambda_m=\Lambda_m^0-A c^{1 / 2}\). The value of the constant A for a given solvent depends on the type of electrolyte along with temperature. According to Kohlrausch law, they value of \(\Lambda_m^0\) for an electrolyte is \(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\nu_{-} \lambda_{-}^0\), where \(\nu_{+}\)and \(\nu_{-}\) are the number of cations and anions, respectively, per molecule of the electrolyte and \(\lambda_{+}^0\) and \(\lambda_{-}^0\) are limiting molar conductivities of cation and anion, respectively. Kohlrausch law finds many applications, like determining the solubility of a sparingly soluble salt, determining the degree of dissociation \(\left(\Lambda_m / \Lambda_m^0\right)\), and the dissociation constant of a weak electrolyte.
If the molar conductance values of Ca²⁺ and Cl^- at infinite dilution are, respectively, 118.8 × 10^-4 ohm^-1 m² mol^-1 and 77.33 × 10^-4 ohm^-1 m² mol^-1, then the molar conductance of CaCl₂ at infinite dilution will be :

1. A 273.46 ohm^-1 m² mol^-1
2. B 196.13 ohm^-1 m² mol^-1
3. C 41.47 ohm^-1 m² mol^-1
4. D -41.47 ohm^-1 m² mol^-1