CUET · CHEMISTRY · PYQ PAPER 2025
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\(KMnO _4\) is prepared by the fusion of \(MnO _2\) with an alkali metal hydroxide and an oxidizing agent like \(KNO _3\) to give a dark-green manganate ion which disproportionate to give permanganate as follows.
\(\begin{array}{l}2 MnO _2+4 KOH + O _2 \rightarrow 2 K_2 MnO _4+2 H _2 O \\ 3 K_2 MnO _4+4 H ^{+} \rightarrow 2 KMnO _4+ MnO _2+2 H _2 O \end{array}\)
On heating \(K _2 MnO _4\) decomposes at 513 K to give \(K _2 MnO _4\). Permanganate ion is tetrahedral and diamagnetic
Acidified \(KMnO _4\) acts a strong oxidizing agent which oxidizes oxalic acid, ferrous ions, nitrite ion and iodides.
HCl is not used to make the medium acidic in oxidation reaction of \(KMnO _4\) in acidic medium, because....
- A \(KMnO _4\) act as reducing agent in the presence of HCl
- B \(KMnO _4\) oxidizes HCl into \(Cl _2\) which is also an oxidizing agent
- C \(KMnO _4\) is a weaker oxidizing agent than HCl
- D both HCl and \(KMnO _4\) act as oxidizing agent
Answer & Solution
Correct Answer
(B) \(KMnO _4\) oxidizes HCl into \(Cl _2\) which is also an oxidizing agent
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Detailed explanation
\(KMnO _4\) oxidizes HCl into \(Cl _2\) which is also an oxidizing agent
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