CUET · CHEMISTRY · PYQ PAPER 2023
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Kinetic studies not only help us to determine the rate of a chemical reaction but also describe the conditions by which the reaction rates can be altered. The factors such as concentration, temperature, pressure and catalyst affect the rate of a reaction.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time.
Rate \(=k[A]^{\text {a }}[B]^{\text {y }}\)
Here \(k\) is the rate constant
\(x+y\) gives the overall order of a reaction, whereas \(x\) and \(y\) repreeent the order with respect to the reactants \(A\) and \(B\), respectively.
Table: Initial rate of formation of NO 2
| S No. | Initial [NO]/mol L-1 | Initial [O2]/mol L-1 | Initial rate of formation of NO2/mol L-1s-1 |
| 1. | 0.30 | 0.3 | 0.096 |
| 2. | 0.60 | 0.3 | 0.384 |
| 3. | 0.30 | 0.6 | 0.192 |
| 4. | 0.60 | 0.6 | 0.768 |
- A Rate of reaction \(=k[ NO ]^2\left[ O _2\right]\)
- B Rate of reaction \(=k[ NO ]\left[ O _2\right]^2\)
- C Rate of reaction \(=k[ NO ]^2\left[ O _2\right]^2\)
- D Rate of reaction \(=k[ NO ]\left[ O _2\right]\)
Answer & Solution
Correct Answer
(A) Rate of reaction \(=k[ NO ]^2\left[ O _2\right]\)
Step-by-step Solution
Detailed explanation
\(\text{Order with respect to NO: } \frac{\text{Rate}_2}{\text{Rate}_1} = \left(\frac{[\text{NO}]_2}{[\text{NO}]_1}\right)^{\text{x}}\) \(\frac{0.384}{0.096} = \left(\frac{0.60}{0.30}\right)^{\text{x}}\) \(4 = (2)^{\text{x}} \Rightarrow x = 2\)…
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