CUET · CHEMISTRY · PYQ PAPER 2025
Read the Passage carefully and answer the Questions
Kinetic studies not only help us to determine the rate of a chemical reaction but also describe the conditions by which the reaction rates can be altered.
The factors such as concentration, temperature, preasure and catalyst affect the rate of a reaction.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time.
Rate \(=k|A|^a[B]^y\)
Here \(k\) is the rate constant
\(x+y\) gives the overall order of a reaction, whereas \(x\) and \(y\) represent the order with respect to the reactants \(A\) and \(B\), respectively.
Table: Initial rate of formation of NO2
| S.No. | Initial [NO]/mol L-1 | Initial [O2]/mol L-1 | Initial rate of formation of [NO2]/mol L-1s-1 |
| 1. | 0.30 | 0.30 | 0.096 |
| 2. | 0.60 | 0.30 | 0.384 |
| 3. | 0.30 | 0.60 | 0.192 |
| 4. | 0.60 | 0.60 | 0.768 |
Based on the above observations, the rate of formation of NO2 can be represented as
- A Rate of reaction \(=k[ NO ]^2\left[ O _2\right]\)
- B Rate of reaction \(=k[ NO ]\left[ O _2\right]^2\)
- C Rate of reaction \(=k[ NO ]^2\left[ O _2\right]^2\)
- D Rate of reaction \(=k[ NO ]\left[ O _2\right]\)
Answer & Solution
Correct Answer
(A) Rate of reaction \(=k[ NO ]^2\left[ O _2\right]\)
Step-by-step Solution
Detailed explanation
Compare Exp. 2 and Exp. 1 for order w.r.t. [NO]: \(\frac{\text{Rate}_2}{\text{Rate}_1} = \frac{k[0.60]^x[0.30]^y}{k[0.30]^x[0.30]^y}\) \(\frac{0.384}{0.096} = \left(\frac{0.60}{0.30}\right)^x\) \(4 = 2^x \implies x=2\) Compare Exp. 3 and Exp. 1 for order w.r.t. [O2]:…
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