ExamBro
ExamBro
CUET · CHEMISTRY · PYQ PAPER 2025

Read the passage carefully and answer the questions based on the passage:
The number of reacting species (atoms, ions or molecules) taking part in an elementary reaction, which must collide simultaneously in order to bring about a chemical reaction is called molecularity of a reaction. In the rate equation Rate \(=k[\mathrm{~A}]^x[\mathrm{~B}]^y\)
\(x\) and \(y\) indicate how sensitive the rate is to the change in concentration of \(A\) and \(B\), respectively. Sum of these exponents, i.e., \(x +y\) gives the overall order of a reaction where \(x\) and \(y\) represent the order with respect to the reactants A and B respectively. Hence, the sum of powers of the concentration of the reactants in the rate law expression is called the order of that chemical reaction. For a first order reaction, the concentration of the reactant varies as \([\mathrm{R}]=[\mathrm{R}]_0 e^{-k t}\)
The initial concentration of \(\mathrm{N}_2 \mathrm{O}_5\) in the following first order reaction
\(\mathrm{N}_2 \mathrm{O}_5(g) \rightarrow 2 \mathrm{NO}_2(g)+1 / 2 \mathrm{O}_2(g)\)

  1. A \(0.040 \mathrm{~min}^{-1}\)
  2. B \(0.023 \mathrm{~min}^{-1}\)
  3. C \(0.032 \mathrm{~min}^{-1}\)
  4. D \(0.050 \mathrm{~min}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.040 \mathrm{~min}^{-1}\)

Step-by-step Solution

Detailed explanation

\(k = \frac{1}{t} \ln\left(\frac{[\mathrm{R}]_0}{[\mathrm{R}]}\right)\) \(k = \frac{1}{10 \mathrm{~min}} \ln\left(\frac{1.24 \mathrm{~mol/L}}{0.83 \mathrm{~mol/L}}\right)\) \(k = \frac{1}{10} \ln(1.49397)\) \(k \approx \frac{1}{10} \times 0.4000\)…
From CUET
Explore more questions on app