Reaction occurring at cathode is
\(HgO+H_2 O+2 e^{-} \rightarrow Hg+2 OH^{-}\)
Above reaction is found in :

Read the passage carefully and answer the questions
Replacement of a hydrogen atom in a hydrocarbon by an alkoxy or carboxyl group yields a class of compounds known as ethers. Ethers are classified as symmetrical or unsymmetrical on the basis of groups attached to the oxygen atoms. Diethyl ether, a symmetrical ether, has been widely used as an inhalation anesthetic. Ethers can be prepared by acid catalyzed intermolecular dehydration of alcohols and Williamson's synthesis. Acid catalyzed dehydration of alcohols is not generally preferred as it gives a mixture of elimination and substitution products. In Williamson's synthesis, an alkyl halide is allowed to react with sodium alkoxide. Ethers containing substituted Alkyl groups may also be prepared by this method. The C-O bond in ether is weakly polar and is cleaved under drastic conditions with excess of hydrogen halides. In electrophilic substitution, the alkoxy group deactivates the aromatic ring and directs the incoming group to ortho and para positions.
Which is most reactive hydrogen halide for cleavage of ethers?

Match List-I and List-II

List-I	List-II
A. Phosphine	I. Catches fire in air
B. Chlorine water	II. Smoke screen
C. White phosphorus	III. Crown structure
D. Sulphur monoclinic and rhombic	IV. Bleaching agent

Choose the correct answer from the options given below:

Read the passage carefully and answer the questions:
The degeneracy of the \(d\) orbitals has been removed due to ligand electron-metal electron repulsions in the octahedral complez to yield three orbitals of lower energy, \(t_{2 g}\) set and two orbitals of higher energy, \(e_g\) set. This splitting of the degenerate levels due to the presence of ligands in a definite geometry is termed as crystal field splitting and the energy separation is denoted by \(\Delta_0\). Thus energy of the two \(e_g\) orbitals will increase by \((3 / 5) \Delta_0\) and that of three \(t_{2 g}\) will decrease by \((2 / 5) \Delta_0\). The crystal field splitting \(\Delta_{\circ}\) depends upon the field produced by the ligand and charge on the metal ion. Some ligands are able to produce strong fields, in which case the splitting will be large, whereas others produce weak fields and consequently result in small splitting of \(d\) orbitals. Relative magnitude of crystal field splitting energy \(\Delta_0\) and pairing energy, \(P\) (energy required for electron pairing in a single orbital) determine the formation of low spin ( \(\Delta_0>P\) ) or high spin ( \(\Delta_0<P\) ) complex. In tetrahedral coordination entity formation, the \(d\)-orbital splitting is inverted and is smaller as compared to the octabedral field splitting. The crystal field theory attributes the colour of the complex to \(d-d\) transition of the electron. The colour of the coordination compounds depends on the crystal field splitting. In the absence of ligand, crystal field splitting does not occur and hence the substance is colourless.
Which of the following relations is correct for the splitting of \(d\) orbitals in octahedral and tetrahedral crystal fields, considering same metal, the same ligands and metal-ligand distances?

Read the passage carefully and answer the Questions
According to Valence Bond theory, the metal atom or ion under the influence of ligands can use its ( \(n-1\) )d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. While the VB theory, to a larger extent, explains the formation, structures and magnetic behaviour of coordination compounds, it suffers from the many shortcomings. The Crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. The five \(d\) orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ion. However, when this negative field is due to ligands in a complex, it becomes asymmetrical and the degeneracy of the \(d\) orbitals is lifted. It results in splitting of the \(d\) orbitals. The pattern of splitting depends upon the nature of the crystal field.
Which among the following are diamagnetic complexes?
\(\left[Ni(CN)_4\right]^{2-},\left[Co\left(C_2O_4\right)_3\right]^{3-},\left[Fe(CN)_6\right]^{4-},\left[CoF_6\right]^{3-},\left[Mn(CN)_6\right]^{3-}\)

Arrange the following in decreasing order of the \(\text{pK}_\text{b}\) value :
(A) \(\text{C}_2\text{H}_5\text{NH}_2\)
(B) \(\text{C}_6\text{H}_5\text{NHCH}_3\)
(C) \((\text{C}_2\text{H}_5)_2\text{NH}\)
(D) \(\text{C}_6\text{H}_5\text{NH}_2\)
(E) \((\text{CH}_3)_3\text{N}\)
Choose the correct answer from the options given below :

Match the properties given in List-I with the metals given in List-II

List-I (Property)	List-II (Metal)
(A) 3d series element with highest melting point	(I) Os
(B) element which can show +8 oxidation state	(II) Fe
(C) 3d series element with largest number of oxidation states	(III) Cr
(D) constituent of Mischmetall	(IV) Mn

Choose the correct answer from the options given below:

Let \(A=\left[a_{i j}\right]\) be a square matrix of order 3 with each entry either 0 or 1 .
Then the number of all such possible matrices is :

If \(A\) is a square matrix of order 3 such that \(|A|=3\) then \(|\operatorname{adj}(\operatorname{adj} A)|\) is equal to:

Name the particle 'X' emitted in the nuclear reaction given below -
\( {}_{11}^{22}Na \rightarrow {}_{10}^{22}Ne + \nu + X \)

The given reaction occur because :
Chlorobenzene \(\frac{\text { Conc. } HNO _3}{\text { Conc. } H _2 SO _4}\) o-Chloronitrobenzene + p-Chloronitrobenzene

Match List-l with List-II:

List-I (Products)	List-II (Organisms)
(A) Statin	(I) Streptococcus
(B) Clot buster	(II) Trichoderma
(C) Swiss cheese	(III) Monascus
(D) Cyclosporin-A	(IV) Propionibacterium

Choose the correct answer from the options given below:

\(\int \frac{\sqrt{16+(\log x)^2}}{x} d x\) is equal to (where \(C\) is an arbitrary constant)