CUET · CHEMISTRY · PYQ PAPER 2023
Rate of a reaction changes from \(2.48 \times 10^{-3}\text{ mol}^{-1}\text{ sec}^{-1}\) to \(4.96 \times 10^{-3}\text{ mol}^{-1}\text{ sec}^{-1}\) when concentration of reactant, is changed from \(0.6\text{ M}\) to \(2.4\text{ M}\) respectively, the order of reaction is :
- A 2
- B zero
- C 0.5
- D 3
Answer & Solution
Correct Answer
(C) 0.5
Step-by-step Solution
Detailed explanation
\( \frac{\text{Rate}_2}{\text{Rate}_1} = \left(\frac{[\text{A}]_2}{[\text{A}]_1}\right)^n \) \( \frac{4.96 \times 10^{-3}}{2.48 \times 10^{-3}} = \left(\frac{2.4}{0.6}\right)^n \) \( 2 = (4)^n \) \( 2 = (2^2)^n \) \( 1 = 2n \) \( n = 0.5 \)
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