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CUET · CHEMISTRY · PYQ PAPER 2023

Rate of a reaction changes from \(2.48 \times 10^{-3}\text{ mol}^{-1}\text{ sec}^{-1}\) to \(4.96 \times 10^{-3}\text{ mol}^{-1}\text{ sec}^{-1}\) when concentration of reactant, is changed from \(0.6\text{ M}\) to \(2.4\text{ M}\) respectively, the order of reaction is :

  1. A 2
  2. B zero
  3. C 0.5
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(C) 0.5

Step-by-step Solution

Detailed explanation

\( \frac{\text{Rate}_2}{\text{Rate}_1} = \left(\frac{[\text{A}]_2}{[\text{A}]_1}\right)^n \) \( \frac{4.96 \times 10^{-3}}{2.48 \times 10^{-3}} = \left(\frac{2.4}{0.6}\right)^n \) \( 2 = (4)^n \) \( 2 = (2^2)^n \) \( 1 = 2n \) \( n = 0.5 \)
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