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CUET · CHEMISTRY · PYQ PAPER 2025

Primary Alkyl halide \(C _4 H _9 Br (X)\) reacts with alcoholic KOH to give the compound \((Y)\). Compound \((Y)\) is reacted with HBr to give \((Z)\) which is an isomer of \((X)\). When \((X)\) is reacted with \(Na /\) dry ether, it gives a compound \((T), C _8 H _{18}\), which is different from the compound formed when \(n\)-butyl bromide is reacted with \(Na /\) dry ether. The correct IUPAC name of (T) is:

  1. A 2,3-Dimethyloctane
  2. B 2,5-Dimethylhexane
  3. C 2,3-Diethylbutane
  4. D 2-Isobutylbutane
Verified Solution

Answer & Solution

Correct Answer

(B) 2,5-Dimethylhexane

Step-by-step Solution

Detailed explanation

X is 1-bromo-2-methylpropane. \(2 \, (CH_3)_2CHCH_2Br \xrightarrow{Na/\text{dry ether}} (CH_3)_2CHCH_2-CH_2CH(CH_3)_2\) IUPAC name of T: 2,5-Dimethylhexane
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