CUET · CHEMISTRY · PYQ PAPER 2025
On doubling the initial concentration, the half life of a reaction becomes half. The order of the reaction is
- A 0.5
- B 0
- C 2
- D 1
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
\(t_{1/2} \propto [A]_0^{1-n}\) \(\frac{t'_{1/2}}{t_{1/2}} = \left(\frac{[A]'_0}{[A]_0}\right)^{1-n}\) \(\frac{1/2 \ t_{1/2}}{t_{1/2}} = \left(\frac{2[A]_0}{[A]_0}\right)^{1-n}\) \(\frac{1}{2} = (2)^{1-n}\) \(2^{-1} = 2^{1-n}\) \(-1 = 1-n\) \(n = 2\)
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