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CUET · CHEMISTRY · PYQ PAPER 2025

On doubling the initial concentration, the half life of a reaction becomes half. The order of the reaction is

  1. A 0.5
  2. B 0
  3. C 2
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

\(t_{1/2} \propto [A]_0^{1-n}\) \(\frac{t'_{1/2}}{t_{1/2}} = \left(\frac{[A]'_0}{[A]_0}\right)^{1-n}\) \(\frac{1/2 \ t_{1/2}}{t_{1/2}} = \left(\frac{2[A]_0}{[A]_0}\right)^{1-n}\) \(\frac{1}{2} = (2)^{1-n}\) \(2^{-1} = 2^{1-n}\) \(-1 = 1-n\) \(n = 2\)
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