CUET · CHEMISTRY · PYQ PAPER 2025
Match List-l with List-ll
| List-l (Rate expression) | List-II (Overall order of reaction) |
| (A) \(r=k[A]^{0.2}[B]^{0.3}[C]\) | (I) \(\frac{3}{10}\) |
| (B) \(r=k[A]^{0.2}[B]^{-0.3}[C]\) | (II) 1 |
| (C) \(r=k[A][B]^{0.8}[C]^{-1}\) | (III) \(3 / 2\) |
| (D)\(r=k[A]^{0.2}[B]^{0.3}[C]^{0.5}\) | (IV) \(9 / 10\) |
- A (А)-(II), (B)-(I), (С)-(III), (D)-(IV)
- B (А)-(I), (B)-(II), (C)-(III), (D)-(IV)
- C (А)-(I), (B)-(II), (C)-(IV), (D)-(III)
- D (А)-(III), (В)-(IV), (C)-(I), (D)-(II)
Answer & Solution
Correct Answer
(D) (А)-(III), (В)-(IV), (C)-(I), (D)-(II)
Step-by-step Solution
Detailed explanation
(A) Overall order \( = 0.2 + 0.3 + 1 = 1.5 = \frac{3}{2} \). (A)-(III) (B) Overall order \( = 0.2 + (-0.3) + 1 = 0.9 = \frac{9}{10} \). (B)-(IV) (C) Overall order \( = 1 + 0.8 + (-1) = 0.8 \). (C)-(I) (Approximate Match assuming typo in question as \(0.8 \ne 0.3\)) (D) Overall…
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