CUET · CHEMISTRY · PYQ PAPER 2023
Match List I with List II
| LIST I (Order) | LIST II (Units of k) |
| A. Zero order reactions | I. \(\backslash s^{-1}\) |
| B. 1st order | II. \(m \operatorname{mol}^{-2} L^2 s^{-1}\) |
| C. 2nd order | III. \(\operatorname{mol} L^{-1} s^{-1}\) |
| D. 3rd order | IV. \(\backslash\) mol \(^{-1} L s^{-1}\) |
- A A-III, B-I, C-II, D-IV
- B A-III, B-II, C-I, D-IV
- C A-III, B-I, C-IV, D-II
- D A-I, B-III, C-IV, D-II
Answer & Solution
Correct Answer
(C) A-III, B-I, C-IV, D-II
Step-by-step Solution
Detailed explanation
A. Zero order reactions: \((mol L^{-1})^{1-0} s^{-1} = mol L^{-1} s^{-1}\) (Match III) B. 1st order: \((mol L^{-1})^{1-1} s^{-1} = s^{-1}\) (Match I) C. 2nd order: \((mol L^{-1})^{1-2} s^{-1} = mol^{-1} L s^{-1}\) (Match IV) D. 3rd order:…
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