CUET · CHEMISTRY · PYQ PAPER 2023
Match List I with List II
| LIST - I | LIST - II |
| A. \(K_4[Fe(CN)_6]\) | I. 3 |
| B. \(K_2SO_4\) | II. 0.5 |
| C. \(CH_3COOH\ \text{ in benzene }\) | III. 5 |
| D. KCl | IV. 2 |
- A A-III, B-I, C-II, D-IV
- B A-III, B-I, C-IV, D-II
- C A-II, B-I, C-III, D-IV
- D A-II, B-III, C-I, D-IV
Answer & Solution
Correct Answer
(A) A-III, B-I, C-II, D-IV
Step-by-step Solution
Detailed explanation
A. For \(K_4[Fe(CN)_6]\): \(n = 4 + 1 = 5\). So, \(i = 5\). B. For \(K_2SO_4\): \(n = 2 + 1 = 3\). So, \(i = 3\). C. For \(CH_3COOH\) in benzene: Association occurs, \(i = 0.5\). D. For KCl: \(n = 1 + 1 = 2\). So, \(i = 2\). A-III, B-I, C-II, D-IV
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