ExamBro
ExamBro
CUET · CHEMISTRY · PYQ PAPER 2025

\(\Lambda_m^{\circ}\) for \(\mathrm{NaCl}, \mathrm{HCl}\), and \(\mathrm{CH}_3 \mathrm{COONa}\) are \(126.4,425.9\), and \(91.0 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\), respectively. Calculate \(\Lambda_m^{\circ}\) for \(\mathrm{CH}_3 \mathrm{COOH}\).

  1. A \(461.3 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  2. B \(425.9 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  3. C \(308.5 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  4. D \(390.5 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(390.5 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\Lambda_m^{\circ}(\mathrm{CH}_3 \mathrm{COOH}) = \Lambda_m^{\circ}(\mathrm{CH}_3 \mathrm{COONa}) + \Lambda_m^{\circ}(\mathrm{HCl}) - \Lambda_m^{\circ}(\mathrm{NaCl})\) \(\Lambda_m^{\circ}(\mathrm{CH}_3 \mathrm{COOH}) = 91.0 + 425.9 - 126.4\)…