CUET · CHEMISTRY · PYQ PAPER 2025
It was found that \(0.1 mol L ^{-1}\) of ammonia took 200 s to be decomposed to half the initial concentration. If the decomposition follows zero order reaction, then the rate constant is
- A \(2.5 \times 10^{-4} mol L ^{-1} s^{-1}\)
- B \(5.0 \times 10^{-4} mol L ^{-1} s^{-1}\)
- C \(2 \times 10^3 mol L ^{-1} s^{-1}\)
- D \(2.5 \times 10^{-3} mol L ^{-1} s^{-1}\)
Answer & Solution
Correct Answer
(A) \(2.5 \times 10^{-4} mol L ^{-1} s^{-1}\)
Step-by-step Solution
Detailed explanation
\(k = \frac{[A]_0}{2t_{1/2}}\) \(k = \frac{0.1 \ mol L^{-1}}{2 \times 200 \ s}\) \(k = 2.5 \times 10^{-4} \ mol L^{-1} s^{-1}\)
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