CUET · CHEMISTRY · PYQ PAPER 2023
In which of the following cases is there a change in oxidation number?
- A Aqueous solution of \(CrO _4^{2-}\) is acidified
- B \(SO _2\) gas is passed through acidified \(Cr _2 O _7^{2-}\) solution
- C \(Cr _2 O _7^{2-}\) solution is made allcaline
- D \(CrO _2 Cl _2\) is dissolved in NaOH
Answer & Solution
Correct Answer
(B) \(SO _2\) gas is passed through acidified \(Cr _2 O _7^{2-}\) solution
Step-by-step Solution
Detailed explanation
In \(Cr_2O_7^{2-}\), Cr oxidation state: \(2x + 7(-2) = -2 \Rightarrow x = +6\). In \(SO_2\), S oxidation state: \(y + 2(-2) = 0 \Rightarrow y = +4\). When \(SO_2\) is passed through acidified \(Cr_2O_7^{2-}\) solution, \(Cr_2O_7^{2-}\) is reduced to \(Cr^{3+}\) and \(SO_2\) is…
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