CUET · CHEMISTRY · PYQ PAPER 2023
In which case there is a change in oxidation number?
- A Aqueous solution of \(\text{CrO}_4^{2-}\) is acidified.
- B \(\text{SO}_2\) gas is passed through acidified \(\text{Cr}_2\text{O}_7^{2-}\) solution.
- C \(\text{Cr}_2\text{O}_7^{2-}\) solution is made alkaline.
- D \(\text{CrO}_2\text{Cl}_2\) is dissolved in \(\text{NaOH}\).
Answer & Solution
Correct Answer
(B) \(\text{SO}_2\) gas is passed through acidified \(\text{Cr}_2\text{O}_7^{2-}\) solution.
Step-by-step Solution
Detailed explanation
Oxidation number of Cr in \( \text{Cr}_2\text{O}_7^{2-} \) = +6 Oxidation number of Cr in \( \text{Cr}^{3+} \) = +3 Oxidation number of S in \( \text{SO}_2 \) = +4 Oxidation number of S in \( \text{SO}_4^{2-} \) = +6 Change in oxidation number occurs.
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