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CUET · CHEMISTRY · PYQ PAPER 2023

In inorganic salt analysis, for the indicatory test of \(Cl^-\), conc. \(H_2SO_4\) is used. This is because:

  1. A Conc. \(H_2SO_4\) is a strong oxidising agent and \(Cl_2\) is produced.
  2. B Conc. \(H_2SO_4\) is a strong reducing agent and HCl is produced.
  3. C Conc. \(H_2SO_4\) is a strong dehydrating agent and \(Cl_2\) is produced.
  4. D Conc. \(H_2SO_4\) has lower volatility than HCl.
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Answer & Solution

Correct Answer

(D) Conc. \(H_2SO_4\) has lower volatility than HCl.

Step-by-step Solution

Detailed explanation

Conc. \(H_2SO_4\) has lower volatility than HCl.
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