CUET · CHEMISTRY · PYQ PAPER 2023
In inorganic salt analysis, for the indicatory test of \(Cl^-\), conc. \(H_2SO_4\) is used. This is because:
- A Conc. \(H_2SO_4\) is a strong oxidising agent and \(Cl_2\) is produced.
- B Conc. \(H_2SO_4\) is a strong reducing agent and HCl is produced.
- C Conc. \(H_2SO_4\) is a strong dehydrating agent and \(Cl_2\) is produced.
- D Conc. \(H_2SO_4\) has lower volatility than HCl.
Answer & Solution
Correct Answer
(D) Conc. \(H_2SO_4\) has lower volatility than HCl.
Step-by-step Solution
Detailed explanation
Conc. \(H_2SO_4\) has lower volatility than HCl.
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