CUET · CHEMISTRY · PYQ PAPER 2023
In a reaction \(2A \to B\), the concentration of A decreases from 0.64 M to 0.22 M in 5 minutes. What is the rate of reaction (in \(M s^{-1}\)) during this interval ?
- A \(7 \times 10^{-4} M s ^{-1}\)
- B \(14 \times 10^{-4} M s ^{-1}\)
- C \(18 \times 10^{-4} M s ^{-1}\)
- D \(24 \times 10^{-4} M s ^{-1}\)
Answer & Solution
Correct Answer
(D) \(24 \times 10^{-4} M s ^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Delta[A] = (0.22 - 0.64)\, M = -0.42\, M\) \(\Delta t = 5 \times 60\, s = 300\, s\) \(Rate = -\frac{1}{2}\frac{\Delta[A]}{\Delta t} = -\frac{1}{2}\frac{-0.42\, M}{300\, s}\) \(Rate = \frac{0.42}{600}\, M s^{-1} = 0.0007\, M s^{-1}\) \(Rate = 7 \times 10^{-4}\, M s^{-1}\)
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