CUET · CHEMISTRY · PYQ PAPER 2023
If we plot graph for first order reaction involving reactant \(R\), then it will be a straight line if plotted for :
- A \([R] /[R]\) against time, \(t\)
- B [R]. against time, \(t\)
- C \(\log [ R ] /[ R ]\). against time, t
- D \([ R ]\) against time, t
Answer & Solution
Correct Answer
(C) \(\log [ R ] /[ R ]\). against time, t
Step-by-step Solution
Detailed explanation
For a first order reaction, the integrated rate law is: \( \ln[R]_t = -kt + \ln[R]_0 \) This equation is in the form \( y = mx + c \). Therefore, plotting \( \ln[R] \) or \( \log[R] \) against time \( t \) yields a straight line. The correct option is: \( \log [ R ] /[ R ] \).…
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