CUET · CHEMISTRY · PYQ PAPER 2025

If the standard electrode potential, \(E_{\text {cell }}^{\circ}=1.10 V\), then the \(E_{\text {cell }}\) for the following reaction at 298 K is
\(Zn ( s )+ Cu ^{2+}(0.1 M ) \rightarrow Zn ^{2+}(0.01 M )+ Cu ( s )\)

A 1.1295 V
B 1.0705 V
C 1.1 V
D \(-1.1295 V\)

Verified Solution

Answer & Solution

Correct Answer

(A) 1.1295 V

Step-by-step Solution

Detailed explanation

\(E_{\text {cell }}=1.10-\frac{0.0591}{2} \log \left(\frac{0.01}{0.1}\right)\)\(\frac{0.01}{0.1}=0.1=10^{-1}\)\(\log \left(10^{-1}\right)=-1\)\(E_{\text {cell }}=1.10-(0.02955 \times-1)\)\(E_{\text {cell }}=1.10+0.02955\)\(E_{\text {cell }}=1.12955 V\)1.1295 V

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List - I with List - II

List - I (Order of reaction)	List - II (Unit)
(A). Zero order reaction	(I). \(L ^2 mol^{-2} s^{-1}\)
(B). First order reaction	(II). \(mol ^{-1} L s ^{-1}\)
(C). Second order reaction	(III). \(mol L ^{-1} s^{-1}\)
(D). Third order reaction	(IV). \(s ^{-1}\)

Choose the correct answer from the options given below:

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If the standard electrode potential, \(E_{\text {cell }}^{\circ}=1.10 V\), then the \(E_{\text {cell }}\) for the following reaction at 298 K is \(Zn ( s )+ Cu ^{2+}(0.1 M ) \rightarrow Zn ^{2+}(0.01 M )+ Cu ( s )\)

Step-by-step Solution

If the standard electrode potential, \(E_{\text {cell }}^{\circ}=1.10 V\), then the \(E_{\text {cell }}\) for the following reaction at 298 K is
\(Zn ( s )+ Cu ^{2+}(0.1 M ) \rightarrow Zn ^{2+}(0.01 M )+ Cu ( s )\)