If the molar conductivities at infinite dilution for \(\mathrm{CH}_3 \mathrm{COOK}, \mathrm{K}_2 \mathrm{SO}_4\) and \(\mathrm{H}_2 \mathrm{SO}_4\) are respectively, \(\mathrm{z}, \mathrm{y}\) and \(\times\left(\mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-1}\right)\), the molar conductivity of \(\mathrm{CH}_3 \mathrm{COOH}\) at infinite dilution will be:

Which of the following reactions has fractional order with respect to one of the reactants?

Propene on addition with bromine in CCl4 gives

Answer the question on the basis of passage given below :
For the transition elements
Sc \(\quad\) Ti \(\quad\) V \(\quad\) Cr \(\quad\) Mn\(\quad\) Fe \(\quad\) Co \(\quad\) Ni \(\quad\) Cu \(\quad\) Zn
Atomic numbers :
21 \(\quad\) 22 \(\quad\) 23 \(\quad\) 24 \(\quad\) 25 \(\quad\) 26 \(\quad\) 27 \(\quad\) 28 \(\quad\) 29 \(\quad\) 30 \(\quad\)
Which transition metal ion \(\text{M}^{2+}\) gives magnetic moment 5.92 BM?

Read the passage carefully and answer the following questions
There are mainly four series of the transition metals, \(3 d\) series ( \(S c\) to Zn), \(4 d\) series (Y to Cd), \(5 d\) series (La and Hf to Hg ) and 6d series which has Ac and elements from Rf to Cn . The two series of the inner transition metals; \(4 f\) ( Ce to Lu ) and \(5 f\) (Th to Lr ) are known as lanthanoids and actinoids respectively. Their chemical properties are transitional between those of \(s\) and \(p\) block elements. The transition metals (with the exception of Zn, Cd and Hg) are very hard and have low volatility. Their melting and boiling points are high. Transition metals have incomplete d subshell either in neutral atom or in their ions. With partly filled d orbitals these elements exhibit certain characteristic properties such as display of a variety of oxidation states, formation of coloured ions and entering into complex formation with a variety of ligands. The transition metals and their compounds are known for their catalytic activity.
In general the electronic configuration of outer orbitals of transition metals is \((n - 1)d^{1-10}ns^{1-2}\) but Pd shows an exceptional electronic configuration as......

A coordination compound \(CrCl _3 \cdot 4 H _2 O\) precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions.
What is the formula of the compound?

Question based on following passage :
Adsorption is the process of attracting and retaining the adsorbate molecules on the surface of adsorbent. It is of two types i.e. Physisrption and chemisorption. To increase the rate of reaction, the substance called 'catalyst' is added. Promotors enhance the activity of catalyst while poison decrease the catalyst activity. Solutions may be true solution, suspension and colloids. Colloids are heterogenous but quite stable. On the basis of nature of interaction, colloids may be Lyophilic or Lyophobic. On the basis of type of dispersed phase particles, there may be multimolecular colloids, macromlecular colloids and associated colloids. The congulation of colloids may be done by boiling, dialysis or by mixing oppositely charged sols.
Reason for the stability of colloidal solution is :

The Mutual inductance \(M _{12}\) of coil 1 with respect to coil 2-

The unit's digit of \(13^{13}\) is :

Consider the LPP, \(\operatorname{Min} Z=2 x-3 y\) subject to the conditions
\(x+y \leq 3\),
\(x \leq 3\),
\(x \geq 0, y \geq 0\)
then the minimum value of the objective function is at the point.

Match List I with List II

List - I (Disease)	List - II (Causal organism)
(A) Pneumonia	(I) Protozoan
(B) Common cold	(II) Roundworm
(C) Malaria	(III) Bacteria
(D) Ascariasis	(IV) Virus

Choose the correct answer from the options given below:

If \(P(A) = \frac{3}{10}, P(B) = \frac{2}{5}\) and \(P(A \cup B) = \frac{3}{5}\), then \(P(B|A) + P(A|B)\) is equal to:

The two positive numbers whose sum is 16 and the sum of whose squares is minimum then the positive numbers are :