CUET · CHEMISTRY · PYQ PAPER 2025
If an electrolyte on dissociation gives \(\nu_{+}\) cations and \(\nu_{-}\) anions, then its limiting molar conductivity is given by
- A \(\Lambda_m^0=\nu_{-} \lambda_{+}^0-\nu_{+} \lambda_{-}^0\)
- B \(\Lambda_m^0=\nu_{+} \lambda_{+}^0-\nu_{-} \lambda_{-}^0\)
- C \(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\nu_{+} \lambda_{-}^0\)
- D \(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\nu_{-} \lambda_{-}^0\)
Answer & Solution
Correct Answer
(D) \(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\nu_{-} \lambda_{-}^0\)
Step-by-step Solution
Detailed explanation
\(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\\nu_{-} \\lambda_{-}^0\)
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