CUET · CHEMISTRY · PYQ PAPER 2023
How much charge is required for the reduction of 0.05 moles of \(MnO _4^{-}\) to \(MnO _2\)?
- A \(5 \times 96500 \times 0.05 C\)
- B \(3 \times 96500 \times 0.05 C\)
- C \(1 \times 96500 \times 0.05 C\)
- D \(2 \times 96500 \times 0.05 C\)
Answer & Solution
Correct Answer
(B) \(3 \times 96500 \times 0.05 C\)
Step-by-step Solution
Detailed explanation
Oxidation state of Mn in \(MnO_4^-\) is \(+7\). Oxidation state of Mn in \(MnO_2\) is \(+4\). Change in oxidation state \( = |+7 - (+4)| = 3\). Moles of electrons needed \( = 0.05 \times 3\). Charge…
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