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CUET · CHEMISTRY · PYQ PAPER 2023

Given that \(\text{E}^{\circ}_{\text{Ni}^{2+}/\text{Ni}} = -0.25 \text{ V}\) and \(\text{E}^{\circ}_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \text{ V}\).
The EMF of the cell containing nickel and copper electrodes in 1 M solution is

  1. A 0.09 V
  2. B 0.59 V
  3. C 0.68 V
  4. D 0.50 V
Verified Solution

Answer & Solution

Correct Answer

(B) 0.59 V

Step-by-step Solution

Detailed explanation

\( \text{E}^{\circ}_{\text{cell}} = \text{E}^{\circ}_{\text{cathode}} - \text{E}^{\circ}_{\text{anode}} \) \( \text{E}^{\circ}_{\text{cell}} = \text{E}^{\circ}_{\text{Cu}^{2+}/\text{Cu}} - \text{E}^{\circ}_{\text{Ni}^{2+}/\text{Ni}} \)…