CUET · CHEMISTRY · PYQ PAPER 2024
For the reaction: \(2 A_2(g)+1 / 4 X ( g ) \rightarrow 2 A_2 X ( g )\), if the volume is increased to double its value by decreasing the pressure, and the reaction is first order with respect to \(X\) and second order with respect to \(A _2\), the rate of reaction will:
- A Decrease by eight times of its initial value
- B Increase by eight times of its initial value
- C Increase by four times of its initial value
- D Remain unchanged
Answer & Solution
Correct Answer
(A) Decrease by eight times of its initial value
Step-by-step Solution
Detailed explanation
Rate \( = k [A_2]^2 [X]\) If volume doubles, \([A_2]' = [A_2]/2\), \([X]' = [X]/2\) Rate' \( = k ([A_2]/2)^2 ([X]/2) = k [A_2]^2 [X] / (4 \times 2) = Rate / 8\) Decrease by eight times of its initial value
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