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CUET · CHEMISTRY · PYQ PAPER 2025

For the following reaction, at equilibrium the Nernst equation may be written as:
\(\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \rightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})\)

  1. A \(E_{\mathrm{Cell}}^o=\frac{2.303 R T}{F} \log \frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]}\)
  2. B \(E_{\mathrm{Cell}}^o=\frac{2.303 R T}{2 F} \log \frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]}\)
  3. C \(E_{\mathrm{Cell}}^o=\frac{2.303 R T}{F} \log \frac{\left[\mathrm{Cu}^{2+}\right]}{\left[\mathrm{Zn}^{2+}\right]}\)
  4. D \(E_{\mathrm{Cell}}^o=\frac{2.303 R T}{2 F} \log \frac{\left[\mathrm{Cu}^{2+}\right]}{\left[\mathrm{Zn}^{2+}\right]}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(E_{\mathrm{Cell}}^o=\frac{2.303 R T}{2 F} \log \frac{\left[\mathrm{Zn}^{2+}\right]}{\left[\mathrm{Cu}^{2+}\right]}\)

Step-by-step Solution

Detailed explanation

\( n = 2 \) \( E_{\mathrm{Cell}} = E_{\mathrm{Cell}}^o - \frac{2.303 RT}{nF} \log Q \) \( \text{At equilibrium, } E_{\mathrm{Cell}} = 0 \text{ and } Q = K_{\mathrm{eq}} = \frac{[\mathrm{Zn}^{2+}]}{[\mathrm{Cu}^{2+}]} \)…
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