ExamBro
ExamBro
CUET · CHEMISTRY · PYQ PAPER 2025

For the cell represented by the following reaction :
\(Mg ( s )+2 Ag ^{+}(0.0001 M ) \rightarrow Mg ^{2+}(0.2 M )+2 Ag ( s )\)
If \(E_{\text {cell }}^{\circ}=3.17 V\), its \(E_{\text {cell }}\) at 298 K will be:
(Given: \(\log _{10} 2=0.301\) )

  1. A 2.96 V
  2. B 2.42 V
  3. C 1.94 V
  4. D 4.5 V
Verified Solution

Answer & Solution

Correct Answer

(A) 2.96 V

Step-by-step Solution

Detailed explanation

\(n=2\) \(Q=\frac{[Mg^{2+}]}{[Ag^{+}]^2} = \frac{0.2}{(0.0001)^2} = 2 \times 10^7\) \(E_{\text{cell}}=E_{\text{cell}}^{\circ}-\frac{0.0591}{n} \log Q\) \(E_{\text{cell}}=3.17-\frac{0.0591}{2} \log (2 \times 10^7)\) \(E_{\text{cell}}=3.17-0.02955 (\log 2 + \log 10^7)\)…
Same subject
Explore more questions on app