CUET · CHEMISTRY · PYQ PAPER 2025
For the cell represented by the following reaction :
\(Mg ( s )+2 Ag ^{+}(0.0001 M ) \rightarrow Mg ^{2+}(0.2 M )+2 Ag ( s )\)
If \(E_{\text {cell }}^{\circ}=3.17 V\), its \(E_{\text {cell }}\) at 298 K will be:
(Given: \(\log _{10} 2=0.301\) )
- A 2.96 V
- B 2.42 V
- C 1.94 V
- D 4.5 V
Answer & Solution
Correct Answer
(A) 2.96 V
Step-by-step Solution
Detailed explanation
\(n=2\) \(Q=\frac{[Mg^{2+}]}{[Ag^{+}]^2} = \frac{0.2}{(0.0001)^2} = 2 \times 10^7\) \(E_{\text{cell}}=E_{\text{cell}}^{\circ}-\frac{0.0591}{n} \log Q\) \(E_{\text{cell}}=3.17-\frac{0.0591}{2} \log (2 \times 10^7)\) \(E_{\text{cell}}=3.17-0.02955 (\log 2 + \log 10^7)\)…
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