CUET · CHEMISTRY · PYQ PAPER 2023
For a particular reaction taking place at \(\text{T} = 300 \text{ K}\), \(\text{E}_a= 300 \text{ kJ/mol}\) and \(\text{log k} = -3.45\); calculate the temperature at which the rate constant becomes 4 times that of k. (Given \(\text{log } 2 = 0.3010\))
- A 400 K
- B 304 K
- C 900 K
- D 1200 K
Answer & Solution
Correct Answer
(B) 304 K
Step-by-step Solution
Detailed explanation
\( \ln \frac{k_2}{k_1} = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) \) \( 2.303 \times 2 \log 2 = \frac{300 \times 10^3 \text{ J/mol}}{8.314 \text{ J K}^{-1} \text{ mol}^{-1}} \left( \frac{1}{300 \text{ K}} - \frac{1}{T_2} \right) \)…
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