CUET · CHEMISTRY · PYQ PAPER 2025
\(\mathrm{CuSO}_4\) is colorless but \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) is blue in color. Which of the following statements is incorrect about the color of \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\)?
- A in \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) water act as ligand
- B crystal field splitting takes place in \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\)
- C presence of \(\mathrm{SO}_4^{2-}\) ion in coordination sphere imparts the color of \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\)
- D d-d transition takes place in \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(C) presence of \(\mathrm{SO}_4^{2-}\) ion in coordination sphere imparts the color of \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\)
Step-by-step Solution
Detailed explanation
The color of transition metal complexes arises due to d-d transitions caused by crystal field splitting when ligands coordinate to the metal ion. In \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\), water molecules act as ligands coordinating to the \(\mathrm{Cu}^{2+}\) ion,…
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