CUET · CHEMISTRY · PYQ PAPER 2023
\(Cr ^{2+}\) is stronger reducing agent than \(Fe ^{2+}\) because :
- A it has exactly full filled configuration
- B \(d^3\) configuration of \(Cr ^{3+}\) is more stable than \(d^5\) configuration of \(Fe ^{3+}\) in aqueous solution
- C oxidises easily to form \(Cr ^{4+}\)
- D \(Fe ^{2+}\) is quite stable and does not oxidise
Answer & Solution
Correct Answer
(B) \(d^3\) configuration of \(Cr ^{3+}\) is more stable than \(d^5\) configuration of \(Fe ^{3+}\) in aqueous solution
Step-by-step Solution
Detailed explanation
\(d^3\) configuration of \(Cr ^{3+}\) is more stable than \(d^5\) configuration of \(Fe ^{3+}\) in aqueous solution
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