CUET · CHEMISTRY · PYQ PAPER 2023
Coagulating power of an ion for a colloidal solution depends on :
- A Its magnitude of charge only
- B Its size only
- C Its tendency to hydrate
- D Its size and magnitude of charge both
Answer & Solution
Correct Answer
(A) Its magnitude of charge only
Step-by-step Solution
Detailed explanation
Its magnitude of charge only
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- Read the passage carefully and answer the Questions
\(KMnO _4\) is prepared by the fusion of \(MnO _2\) with an alkali metal hydroxide and an oxidizing agent like \(KNO _3\) to give a dark-green manganate ion which disproportionate to give permanganate as follows.
\(\begin{array}{l}2 MnO _2+4 KOH + O _2 \rightarrow 2 K_2 MnO _4+2 H _2 O \\ 3 K_2 MnO _4+4 H ^{+} \rightarrow 2 KMnO _4+ MnO _2+2 H _2 O \end{array}\)
On heating \(K _2 MnO _4\) decomposes at 513 K to give \(K _2 MnO _4\). Permanganate ion is tetrahedral and diamagnetic
Acidified \(KMnO _4\) acts a strong oxidizing agent which oxidizes oxalic acid, ferrous ions, nitrite ion and iodides.
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