CUET · CHEMISTRY · PYQ PAPER 2025
Calculate the molality of 25 g of ethanoic acid \(CH(_3\)\(\mathrm{COOH}\)) in 250 g benzene
- A \(16.64 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- B \(1.664 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- C \(166.4 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- D \(6.64 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Answer & Solution
Correct Answer
(B) \(1.664 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Step-by-step Solution
Detailed explanation
\(M_{CH_3COOH} = 2(12.01) + 4(1.01) + 2(16.00) = 60.06 \, \mathrm{g/mol}\) \(n = \frac{25 \, \mathrm{g}}{60.06 \, \mathrm{g/mol}} = 0.41625 \, \mathrm{mol}\) \(m = \frac{0.41625 \, \mathrm{mol}}{0.250 \, \mathrm{kg}} = 1.665 \, \mathrm{mol/kg}\)
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