ExamBro
ExamBro
CUET · CHEMISTRY · PYQ PAPER 2025

Calculate the Gibbs free energy for the given reaction, with the standard electrode potential equal to 1.1 V
\(Zn ( s )+ Cu ^{2+}( aq ) \rightarrow Zn ^{2+}( aq )+ Cu ( s )\)

  1. A \(-106.15 kJ / mol\)
  2. B \(212.27 kJ / mol\)
  3. C \(-212.27 kJ / mol\)
  4. D \(-312.4 kJ / mol\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-212.27 kJ / mol\)

Step-by-step Solution

Detailed explanation

\(n = 2\) \(\Delta G = -nFE^\circ = -(2)(96485 \,C/mol)(1.1 \,V) = -212267 \,J/mol = -212.27 \,kJ/mol\)
Same subject
Explore more questions on app