CUET · CHEMISTRY · PYQ PAPER 2023
Answer the question on the basis of passage given below:
Second period elements of p-Block differs from the rest of their group members due to their small atomic size, high electronegativity, high ionization enthalpy and absence of d-orbitals. The elements from the second period like C, N, O have unique property of forming \(p \pi-p \pi\) multiple bonds whereas other heavier elements of p-block form \(d \pi-p \pi\) multiple bonds. This changes the properties of second period elements to great extent. Also the single bond strength of the p-block elements with their own atoms gets affected by their atomic size and presence of lone pairs.
Inert pair effect also affects the properties of the p-Block elements especially for those elements which are present from 4th period onward and this happens due to poor screening effect of inner (n-1)d subshell electrons.
\(\text{N}_2\) is a gas wherein \(\text{P}_4\) is a solid, because -
- A Nitrogen is having higher electronegativity than phosphorus
- B Nitrogen can form \(p \pi-p \pi\)bond while phosphorus cannot do so.
- C Atomic size of nitrogen is smaller than phosphorous
- D \(\text{N}_2\) is a non-polar molecular species whereas phosphorus in solid state forms polar bonds
Answer & Solution
Correct Answer
(B) Nitrogen can form \(p \pi-p \pi\)bond while phosphorus cannot do so.
Step-by-step Solution
Detailed explanation
Nitrogen forms stable \(\text{N}_2\) molecules with a strong triple bond through \(p \pi-p \pi\) overlap. Due to its larger size, phosphorus cannot form effective \(p \pi-p \pi\) multiple bonds and instead forms single bonds in a tetrahedral \(\text{P}_4\) structure. The…
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