Answer the question on the basis of passage given below :
There are some deposits of nitrates and phosphates in the earth’s crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under laboratory conditions, but microbes do it easily. Ammonia forms a large number of complexes with transition metals. Hybridisation easily explains the ease of sigma donation capability of NH₃ and PH₃. Phosphine is an inflammable gas, prepared from white phosphorus.
\(P H _3\) is a better reducing agent than \(NH _3\) because :

The conductivity of an electrolytic solution does not depend on

An element has a cubic close packing (ccp) structure with an edge length 297 pm . The density of mass \(=107.9 g / mol\).)
the element is (Given molar mass = \(107.9 g / mol\).)

The correct increasing order of reactivity of alkyl halides with \(CH _3 NH _2\) is
(A) \(C _2 H _5- Br\)
(B) \(C _2 H _5- I\)
(C) \(C _2 H _5- F\)
(D) \(C _2 H _5- Cl\)
Choose the correct answer from the options given below:

Read the passage carefully and answer the questions based on the passage:
Alcohols are versatile compounds as they can act as both nucleophile and electrophile. They undergo reactions based on cleavage of \(\mathrm{O}-\mathrm{H}\) and \(\mathrm{C}-\mathrm{O}\) bonds. The cleavage of \(\mathrm{O}-\mathrm{H}\) bond reflects the acidic character of alcohols. However they are weaker acids than water, phenol and carboxylic acids. Alkoxide ion formed by loss of proton from the OH group of alcohols reacts with water to form the corresponding conjugate acid - base pair. They act as Bronsted base due to presence of unshared electron pairs on oxygen.Both alcohols and phenol react with carboxylic acids, acid chlorides and anhydrides to form esters. The introduction of acetyl group in alcohols or phenol is known as acetylation. Alcohols react with hydrogen halides to form alkyl halides which form the basis of Lucas test. They also undergo acid catalyzed dehydration to form alkenes. Alcohols can be easily oxidized with variety of oxidizing agents. The nature of the product depends on the type of oxidizing agent and the nature of alcohol.
Oxidation of alcohols involves formation of carbon oxygen double bond with

Match the complex species given in List-l with the possible isomerism given in List-ll:

List-l Complex species	List-ll Isomerism
(A) \(\left[ Co \left( NH _3\right)_4 Cl _2\right]^{+}\)	(I) optical
(B) cis- \(\left[ Co ( en )_2 Cl _2\right]^{+}\)	(II) ionization
(C) \(\left[ Co \left( NH _3\right)_5\left( NO _2\right)\right] Cl _2\)	(III) coordination
(D) \(\left[ Co \left( NH _3\right)_6\right]\left[ Cr ( CN )_6\right]\)	(IV) geometrical

Choose the correct answer from the options given below:

The reaction of neutral \(M n O 4 ^{ \wedge }\) - and \(I ^{ \wedge }\) - gives

Two parallel beams of monochromatic light pass through a long slit of width 0.2 mm one by one. The angular divergence in which most of the light is diffracted for both the beams are \( 2.25 \times 10^{-3} \text{ rad} \) and \( 4.50 \times 10^{-3} \text{ rad} \) respectively. If the wavelength of the first beam is \( \lambda_1 = 3000 \text{ Å} \), then the wavelength of the second beam is:

\(\int \frac{e^{2 x}-e^{-2 x}}{e^{2 x}+e^{-2 x}} d x \) is equal to :

A magnetic field B exists in a direction perpendicular to the plane of a square loop made of metal wire. The wire has a diameter of 4 mm and a total length of 30 cm. The magnetic field B changes at a steady rate of \( 0.032 \text{ T s}^{-1} \). The induced current in the closed loop is\n(Given: Resistivity of the metal wire is \( \rho = 1.57 \times 10^{-8} \Omega \text{ m} \))

Find the least non-negative remainder obtained when \(3^{128}\) is divided by \(7\) .

The sum of order and degree of the differential equation \(y=x \frac{d y}{d x}+2 \sqrt{1+\left(\frac{d y}{d x}\right)^2}\) is

Which of the following is an example of a sex linked disorder?