CUET · CHEMISTRY · PYQ PAPER 2023
Answer the question on the basis of passage given below :
One of the notable features of the transition element is the great variety of oxidation states it may show in its compounds. The elements which give the greatest number of oxidation states occur in or near the middle of the series. Manganese, for example exhibits all the oxidation states from +2 to +7. The lesser number of oxidation states at the extreme ends is either due to losing or sharing of few electrons (Sc, Ti) or too many d electrons of higher valence. Early in the first series scandium (II) is virtually unknown and titanium (IV) which is more stable than Ti (III) or Ti (II). On the other end, the only oxidation state of zinc is \(+ 2\).
Cris reducing but Mn is oxidising in nature although both have \(d ^{ 1 }\) configuration. It is due to the reason that Cr configuration changes from
- A \(d^1\) to \(d^3\)
- B \(d ^1\) to \(d ^4\)
- C \(d ^2\) to \(d ^3\)
- D \(d ^{\circ}\) to d 10
Answer & Solution
Correct Answer
(A) \(d^1\) to \(d^3\)
Step-by-step Solution
Detailed explanation
\( \text{Cr(V) has configuration } d^1 \) \( \text{Cr(III) has configuration } d^3 \) \( \text{A change from } d^1 \text{ to } d^3 \text{ involves gaining 2 electrons (reduction)} \)
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