CUET · CHEMISTRY · PYQ PAPER 2023
"Answer the question on basis of passage given below:
\(G = \frac{\kappa A}{l}\)=k (both \(A\) and \(l\) are unity in their appropriate units in m or cm)
Molar conductivity of a solution at a given concentration is the conductance of the volume \(V\) of solution containing one mole of electrolyte kept between two electrodes with area of cross section \(A\) and distance of unit length (\(l\)). Therefore,
\(\Lambda_m = \frac{\kappa A}{l}\)
Since \(l = 1\) and \(A = V\) (volume containing 1 mole of electrolyte),
\(\Lambda_m = \kappa V\)
If the length \(l\) in the column of an electrolytic cell is halved and its area of cross-section is tripled, then conductance (\(G\)) would become:"
- A 2 times
- B \(\frac{1}{2}\) times
- C 6 times
- D \(\frac{1}{6}\) times
Answer & Solution
Correct Answer
(C) 6 times
Step-by-step Solution
Detailed explanation
\(G = \frac{\kappa A}{l}\) \(l' = \frac{l}{2}\), \(A' = 3A\) \(G' = \frac{\kappa A'}{l'} = \frac{\kappa (3A)}{(l/2)}\) \(G' = 6 \frac{\kappa A}{l} = 6G\)
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