Answer the question on basis of passage given below :
The noble gases He to Rn have close shell configuration and are monoatomic gases under normal conditions. Though mostly unreactive, but direct reaction of Xe with \(F_2\) leads to a series of compounds with Xe oxidation numbers \(+2,+4\) and +6 . When certain compounds like phenol and quinol are crystallised in the presence of noble gas such as \(Ar , Kr\) and Xe a category of compound called clathrates are formed. In these the noble gas atoms are trapped in the cavities of the crystal lattices. The compounds which crystallise are known as hosts (H) while the noble gas atoms are called guests ( \(G\) ). The general formula of a clathrate compound is \(n H m G\), where \(n\) is the number of host molecules and m is the number of atoms a molecule of guest.
In what molar ratio must Xe and \(F_2\) be taken to give \(XeF _4\) ?

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The degeneracy of the \(d\) orbitals has been removed due to ligand electron-metal electron repulsions in the octahedral comples to yield three orbitals of lower energy, \(t_{2 g}\) set and two orbitals of higher energy, \(e_g\) set. This splitting of the degenerate levels due to the presence of ligands in a definite geometry is termed as crystal field splitting and the energy separation is denoted by \(\Delta_0\). Thus energy of the two \(e_g\) orbitals will increase by \((3 / 5) \Delta_0\) and that of three \(t_{2 g}\) will decrease by \((2 / 5) \Delta_0\). The crystal field splitting \(\Delta_0\) depends upon the field produced by the ligand and charge on the metal ion. Some ligands are able to produce strong fields, in which case the splitting will be large, whereas others produce weak fields and consequently result in small splitting of \(d\) orbitals. Relative magnitude of crystal field splitting energy \(\Delta_{\circ}\) and pairing energy, \(P\) (energy required for electron pairing in a single orbital) determine the formation of low spin ( \(\Delta_0>P\) ) or high spin ( \(\Delta_0<P\) ) complex. In tetrahedral coordination entity formation, the \(d\)-orbital splitting is inverted and is smaller as compared to the octahedral field splitting. The crystal field theory attributes the colour of the complex to \(d-d\) transition of the electron. The colour of the coordination compounds depends on the crystal field splitting. In the absence of ligand, crystal field splitting does not occur and hence the substance is colourless.
Choose the correct order of the ligands in their increasing crystal field splitting:

What is the maximum molarity of \(MgCl_2\) in aqueous solution,
if its solubility product is \(4 \times 10^{-28}\)? 

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Alcohols and phenol are formed when a hydrogen atom in a hydrocarbon, aliphatic and aromatic respectively, is replaced by \(\text{-OH}\) group. The substitution of a hydrogen atom in a hydrocarbon by an alkoxy or aryloxy group forms ethers. Alcohols and phenol consist of two part, an alkyl/aryl group and a hydroxyl group. The properties of alcohols and phenols are primarily due to the hydroxyl group. The nature of alkyl and aryl groups simply modify these properties. Alcohol react both as nucleophiles and electrophiles whereas in phenols, the reactions that take place on the aromatic ring are electrophilic subtitution reactions.
Aspirin is an acetylation product of :

In the following sequence of reactions :
CH3–CH(NH2) - CH3 $\xrightarrow{HNO_2}$[A] $\xrightarrow{Oxidation}$[B] $\xrightarrow{H^{+}/H_{2}O}$ CH3MgBr
[C] The compound [C] is :

The oxoacid of sulphur which has a lone pair of electron on sulphur atom is:

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The term vitamin was coined from the word vital +amine since the earlier identified compounds had amino groups. Later work showed that most of them didn't contain amino groups, so the letter "e" was dropped and ther term vitamin is used these days.
Vitamins are classified into two groups depending upon their solubility in water or fat. Fat soluble vitamins are soluble in fat and oils but insoluble in water. They are stored in liver and adipose (fat storing) tissues. Water-soluble vitamins are soluble in water. They must be supplied regularly in the diet as they are readily excreated in urine.
Which Vitamin is known as Pyridoxine?

A long straight wire is carrying a current of 20 A. An electron is moving with a speed of \( 10^7 \text{ m/s} \) parallel to the wire. The force experienced by the electron when it is 2 cm away from the wire is:

Vitamin B12 is a coordination compound of _______

Arrange the following stages of primary succession in water in correct sequence.
A. Rooted submerged plants
B. Marsh meadows
C. Phytoplanktons
D. Scrubs followed by trees
E. Free floating plants
Choose the correct answer from the options given below:

Let \(R\) be the relation in the set \(\{1,2,3\}\) given by \(R=\{(1,1),(2,2),(3,3),(1,2),(2,3)\}\). Choose the correct answer.

An electric field in \(x-y\) plane is given by the equation \(\vec{E}=E_0 \hat{i} N / C\). A positively charged particle is given a velocity of \(5 \hat{j} m / s\) at point \(x=3, y=0\) in \(x-y\) plane. The particle will experience force :

Match List-I with List-II

List - I	List - II
(A) Vitamin B1	(I) Ascorbic Acid
(B) Vitamin B2	(II) Pyridoxine
(C) Vitamin B6	(III) Riboflavin
(D) Vitamin C	(IV) Thiamine

Choose the correct answer from the options given below: