CUET · CHEMISTRY · PYQ PAPER 2023
An aqueous solution of glucose is labelled as 20% w/w. If the density of the solution is 1.2 g/mL the molality of the solution.
- A 5.38 mole/kg
- B 4.21 mole/kg
- C 2.76 mole/kg
- D 1.38 mole/kg
Answer & Solution
Correct Answer
(D) 1.38 mole/kg
Step-by-step Solution
Detailed explanation
Mass of glucose = 20 g Mass of water = 100 g - 20 g = 80 g = 0.080 kg Moles of glucose (\(C_6H_{12}O_6\)) = \( \frac{20 \text{ g}}{180 \text{ g/mol}} = \frac{1}{9} \text{ mol} \) Molality = \( \frac{1/9 \text{ mol}}{0.080 \text{ kg}} \approx 1.38 \text{ mol/kg} \)
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