CUET · CHEMISTRY · PYQ PAPER 2023
Activation energy (\(E_a\)) and rate constants (\(K_1\) and \(K_2\)) at two different temperature \(T_1\) and \(T_2\) respectively for a chemical reaction are related as :
- A \(\ln \frac{K_2}{K_1} = \frac{E_a}{2.303R} \left[\frac{1}{T_1} - \frac{1}{T_2}\right]\)
- B \(\ln \frac{K_2}{K_1} = - \frac{E_a}{R} \left[\frac{1}{T_2} - \frac{1}{T_1}\right]\)
- C \(\ln \frac{K_2}{K_1} = \frac{E_a}{R} \left[\frac{1}{T_1} - \frac{1}{T_2}\right]\)
- D \(\ln \frac{K_2}{K_1} = \frac{E_a}{2.303} \left[\frac{1}{T_1} - \frac{1}{T_2}\right]\)
Answer & Solution
Correct Answer
(C) \(\ln \frac{K_2}{K_1} = \frac{E_a}{R} \left[\frac{1}{T_1} - \frac{1}{T_2}\right]\)
Step-by-step Solution
Detailed explanation
\(\ln \frac{K_2}{K_1} = \frac{E_a}{R} \left[\frac{1}{T_1} - \frac{1}{T_2}\right]\)
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