A divalent ion of 'V' (Atomic no. - 23) in aqueous solution is :

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In the formation of coordination complexes, if the inner \(d\) orbital \((n-1) d\) is used in hybridisation, the complex, is called an inner orbital or low spin or spin paired complex. And if it uses outer \(d\) orbital ( \(n d\) ) in hybridisation (like \(s p^3 d^2\) ), it is called outer orbital or high spin or spin free complex. The degeneracy of the \(d\) orbitals has been removed due to ligand electron-metal electron repulsions in the complex. This splitting of the degenerate levels due to the presence of ligands in a definite geometry is termed as crystal field splitting. For coordination complexes, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the 'spin-only' formula, \(\mu=\sqrt{n(n+2)}\) where \(n\) is the number of unpaired electrons and \(\mu\) is the magnetic moment in units of Bohr magneton (BM). The coordination compounds are of great importance. These compounds are widely present in the mineral, plant and animal worlds and are known to play many important functions in the area of analytical chemistry, metallurgy, biological systems, industry and medicine.
The CFSE for tetrahedral \(\left[ CoCl _4\right]^{2-}\) is \(8000 cm^{-1}\), the CFSE for octahedral \(\left[ CoCl _6\right]^{4-}\) will be........

Which of the following pairs of solutions are isotonic?

Which of the following is used as a catalyst in contact process?

The rate constant for a reaction \(\text{P} \rightarrow \text{Q}\) is \(0.8 \times 10^{-3} \text{ mol L}^{-1} \text{ s}^{-1}\).
If the concentration of P is 10 M, then the concentration of Q after 40 minutes is:

The decomposition of N\(_2\)\(\mathrm{O}_5\) in CCl\(_4\) at 318K has been studied by monitoring the concentration of N\(_2\)\(\mathrm{O}_5\) in the solution. Initially, the concentration of N\(_2\)\(\mathrm{O}_5\) is 2.33 mol/L and after 184 minutes, it is reduced to 2.08 mol/L. The reaction takes place according to the equation
2N\(_2\)\(\mathrm{O}_5\)(g) \(\rightarrow\) 4NO\(_2\)(g) + O\(_2\)(g)
The average rate of this reaction in different units will be:

Osmotic pressure measurements are less accurate and difficult to carry out. Therefore, this method is not useful for measuring molecular weights. But it is used to find out molecular weights of polymers eg. plastics, proteins and starch having many monomer units. Knowing the value of osmotic pressure of a given solution, molecular weight of the solute can be calculated using Van't Hoff equation.
When osmatic pressure and temperature for two solutions are same, equal volumes of solutions would contain same number of:

If \(\vec{a}+\lambda \vec{b}\) is perpendicular to \(\vec{c}\), where
\(\vec{a}=-\hat{i}+2 \hat{j}+\hat{k}, \vec{b}=3 \hat{i}+2 \hat{j}+\hat{k}\), and \(\vec{c}=\hat{i}-\hat{j}\),
then :

The reaction shown above is known as

In Bohr's atomic model, the radius of the first orbit is \( r_o \). The radius of the third orbit will be :

Consider the line \(\vec{r}=-2 \hat{i}+3 \hat{j}+\hat{k}+\lambda(5 \hat{i}-3 \hat{j}-\hat{k})\). Match List-I with List-II

List-I	List-II
(A) A point on the given line	(I) \(\left(\frac{5}{\sqrt{35}}, \frac{-3}{\sqrt{35}}, \frac{-1}{\sqrt{35}}\right)\)
(B) Direction ratios of the given line	(II) (2, 3, 1)
(C) Direction cosines of the given line	(III) (5, -3, -1)
(D) Direction ratios of a line perpendicular to given line	(IV) (-2, 3, 1)

Choose the correct answer from the options given below:

A person has purchased a home for Rs. 10,00,000 with a down payment of Rs. 2,00,000. He amortizes the balance at 9% per annum compounded monthly for 25 years.
Then the equal monthly instalment (EMI) is :
[Given that \(\frac{(1.0075)^{300}-1}{(0.0075)(1.0075)^{300}}=119.1616\) ]

A cell is formed by combining given electrodes with \(Zn ^{2+} \mid Zn ( s )\left(E^{\circ}=-0.76 V\right)\). Arrange the following in decreasing order of \(E _{\text {cell }}^{\circ}\).
Cell Notation: \(Zn ( s ) \mid Zn ^{2+} \|\) Given electrode
(A) \(Ag ^{+} \mid Ag ( s ): E^{\circ}=+0.80 V\)
(B) \(Na ^{+} \mid Na ( s ): E^{\circ}=-2.71 V\)
(C) \(Fe ^{2+} \mid Fe ( s ): E^{\circ}=-0.44 V\)
(D) \(Cu ^{+} \mid Cu ( s ): E^{\circ}=+0.52 V\)
Choose the correct answer from the options given below: