CUET · CHEMISTRY · PYQ PAPER 2025

\(2 N_2 O _5 \rightarrow 4 NO _2+ O _2\)
At a given instant of time, the rate and rate constant are 1.02 \(\times\) 10\(^-\)\(\mathrm{4}\) mol L\(^-\)\(\mathrm{1}\) s\(^-\)\(\mathrm{1}\) and 3.4 \(\times\) 10\(^-\)\(\mathrm{5}\) s\(^-\)\(\mathrm{1}\), respectively.
The concentration of N\(_2\)\(\mathrm{O}\)_5 at that time will be:

A \(3.0 \mathrm{~mol} \mathrm{~L}^{-1}\)
B \(1.713 \mathrm{~mol} \mathrm{~L}^{-1}\)
C \(1.02 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}\)
D \(3.4 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(3.0 \mathrm{~mol} \mathrm{~L}^{-1}\)

Step-by-step Solution

Detailed explanation

\( \text{Rate} = k[\text{N}_2\text{O}_5] \) \( [\text{N}_2\text{O}_5] = \frac{\text{Rate}}{k} \) \( [\text{N}_2\text{O}_5] = \frac{1.02 \times 10^{-4} \text{ mol L}^{-1}\text{ s}^{-1}}{3.4 \times 10^{-5} \text{ s}^{-1}} \) \( [\text{N}_2\text{O}_5] = 3.0 \text{ mol L}^{-1} \)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List - I with List - II.

List - I (Polymer)	List - II (Monomer)
(A) Nylon 2-nylon 6	(I) Ethylene glycol and Benzene-1,2-dicarboxylic acidne
(B) Neoprene	(II) Glycine and Amino caproic acid
(C) Glyptal	(III) Adipic acid and Hexamethylene diam
(D) Nylon 6, 6	(IV) 2-chlorobuta-1,3-diene

Choose the correct answer from the options given below :

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