CUET · CHEMISTRY · PYQ PAPER 2023
0.5 molal aqueous solution of a weak acid (HX) is 20% ionised.
If \(\text{K}_\text{f}\) for water is 1.86 \(\text{K kg mol}^{-1}\) the lowering in freezing point of solution will be:
- A \(0.56\text{K}\)
- B \(1.12\text{K}\)
- C \(-0.56\text{K}\)
- D \(-1.12\text{K}\)
Answer & Solution
Correct Answer
(B) \(1.12\text{K}\)
Step-by-step Solution
Detailed explanation
\(i = 1 + (n-1)\alpha\) \(i = 1 + (2-1) \times 0.20 = 1.20\) \(\Delta T_f = i \cdot K_f \cdot m\) \(\Delta T_f = 1.20 \times 1.86 \text{ K kg mol}^{-1} \times 0.5 \text{ mol kg}^{-1} = 1.116 \text{ K}\) \(\Delta T_f \approx 1.12 \text{ K}\)
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