CUET · CHEMISTRY · PYQ PAPER 2023
0.1 M NaCl solution has lower freezing point than \(0.1 M MgCl _2\) solution in water because:
- A \(MgCl _2\) is less ionic than NaCl
- B Vant-Hoff factor (i) for NaCl is more than \(MgCl _2\)
- C Vant-Hoff factor for \(MgCl _2\) is more than NaCl
- D NaCl is less ionic than \(MgCl _2\)
Answer & Solution
Correct Answer
(C) Vant-Hoff factor for \(MgCl _2\) is more than NaCl
Step-by-step Solution
Detailed explanation
For NaCl: \(i \approx 2\) For MgCl2: \(i \approx 3\) Vant-Hoff factor for \(MgCl _2\) is more than NaCl.
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